A circular coil of wire 8 cm in diameter has 12 turns and carries a current of 5 A. The coil is in a field where the magnetic induction is 0.6 T. a. What is the maximum torque on the coil? b. In what position would the torque be half as great as in (i) ?
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Answer:
M
×
B
τ
max
=MB
M=NIA=NIπR
2
Length=N×circumference⟹L=N2πR
⟹R=
2πN
L
M=NIπ
4π
2
N
2
L
2
=
4πN
IL
2
τ
max
=
4πN
IL
2
B
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