Physics, asked by montusingh3122, 11 months ago

a circular coil of wire consisting of hundred turn each of radius 8.0 centimetre carries a current of 0.4 T A what is the magnitude of magnetic field at the centre of the coil​

Answers

Answered by yashyesh
0

Answer:

B at the center of a current carrying coil is given by B= μ₀NI/2R

Explanation:

μ₀=4π×10⁻⁷

now if you substitute

B=4×3.14×10⁻⁷×100×0.4/8×10⁻²

B=6.28×10⁻⁴ T

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