Question

A circular copper-ring of radius r translates in its plane with a constant velocity v. A uniform magnetic field B exists in the space in a direction perpendicular to the plane of the ring. Consider different pairs of diametrically opposite points on the ring. (a) Between which pair of points is the emf maximum? What is the value of this maximum emf? (b) Between which pair of points is the emf minimum? What is the value of this minimum emf ?

Answer 1

EMF depends upon Placement of End Point

Explanation:

(a) In between the end points of diameter perpendicular to velocity the emf value is maximum..

$E_m_a_x$ = vB(2R) is the equation which gives emf maximum value.

(b) Similarly, between end points of diameter being parallel to ring velocity, emf is minimum.

$E_m_i_n$ = 0 is the equation which gives emf minimum value.

Answer 2

(a) The maximum emf value is given in

$E_{max}$ = vB(2R)

(b) The minimum emf value is defined by

$E_{min}$ = 0

Explanation:

Within its plane a circular copper-wire of radius r converts with a constant v (velocity) . A standard magnetic field B occurs within space in a path perpendicular to the wire plane.

(a) The mean emf value is perpendicular to velocity between the nodes of the diameter.

The maximum emf value is given in

$E_{max}$ = vB(2R)

(b) The minimum value of electro-Motive force is in accordance with the ring velocity between the nodes of the diameter.

The minimum emf value is defined by

$E_{min}$ = 0

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