Question

A circular culvert of `4.0m` diameter has the depth of water for maximum velocity of​

Answer 1

Answer:

Step-by-step explanation:

≈ (0.2 to 235.1) × wavelength of an audible sound to a human ( 4×10^-5 to 0.05 speed of sound/Hz )

VHF (very high frequency) | meter band

Light travel time t in vacuum from t = x/c:

| 13 ns (nanoseconds)

Distance to horizon (ignoring topography and other obstructions):

| 7.1 km (kilometers)

| 7143 meters

| 4.4 miles

Spectroscopic wavenumber ν^~ from ν^~ = 2π/ƛ:

| 1.6 m^(-1) (reciprocal meters)

Frequency ν of a photon in a vacuum from ν = c/λ:

| 75 MHz (megahertz)

Wavenumber k from k = 2π/λ:

| 1.6 m^(-1) (reciprocal meters)