A circular disc is rotating about its own axis at the rate of 200revolutions per minute.Two particles P,Q of disc are at distances 5cm,10cm from axis of rotation.The ratio of angular velocities of P and Q is
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Angular frequency = f = 200rpm
Angular speed = ω = 2πf = 400π rad/min
During circular motion particles of the system revolves with angular velocity , but they have different tangential velocity
angular velocity of P = angular velocity of Q
ω of P/ω of Q = (400πrad/min)/(400πrad/min) = 1:1
Angular speed = ω = 2πf = 400π rad/min
During circular motion particles of the system revolves with angular velocity , but they have different tangential velocity
angular velocity of P = angular velocity of Q
ω of P/ω of Q = (400πrad/min)/(400πrad/min) = 1:1
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4
Answer:
1:1
Explanation:
f=200rpm
w=2πf
400 rad/minutep=q
w(p)/w(q)=400π rad/min/400πrad/min
=1:1
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