Question

a circular disc of mass 10kg and radius 0.2m/sec is set into rotation about an axis passing through its centre and perrpendicular to its plane by applying torque of 10nm .calculate the angular velocity of the disc at the end of 6seconds from start

Answer 1

The angular velocity of the disc at the end of 6 seconds from start is 300 rad / s.

Explanation:

Moment of inertia "I" = mr^2 / 2} =  10 x 0.2^2 / 2

                                  = 0.2 kg m^2

Angular acceleration  α =  I/  τ =  10 / 0.2  =50 rad/s^2

Initial angular velocity "w"  i  = 0

Using  wf  = w i  + αt

wf  = 0 + 50 × 6 = 300 rad / s

Hence the angular velocity of the disc at the end of 6 seconds from start is 300 rad / s.

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