Question

A circular field of radius 41 m has a circular path of uniform width 5 m along and inside its
boundary. Find the cost of paving the path at * 25 per sq. metre.
Find :​

Answer 1

Answer:

30250 rs

Step-by-step explanation:

Arae of outer circle = πr^2

$\frac{22}{7} \times 41 \times 41 \\ 5283.14 {m}^{2}$

area of inner circle whose radius = 41-5=46

πr^2

$\frac{22}{7} \times 36 \times 36 = 4073.14 {m}^{2}$

Now Area of path = Area of outer cicle - Area of inner circle = 5283.14-4073.14=

1210m^2

$cost \: of \: paving \: 1 {m}^{2 } = 25rs$

$cost \: of \: paving \: 1210 {m}^{2} = 1210 \times 25 = 30250rs$