Question

a circular flower bed is surrounded by a path 4 m wide the diameter of the flower bed is 66 M what is the area of this path.
(pie = 3.14)

Answer 1

Answer:

427.04 m²

Step-by-step explanation:

The circular flower bed is surrounded by a circular path.

The radius of the flower bed = 66/2 = 33 m

Area of the flower bed = πr² => 3.14 × 33 × 33

=> 3419.46  m²

The radius of the flower bed + the path = (66+4)/2 => 70/2 = 35 m

Its area = πr² => 3.14 × 35 × 35

=>3846.5 m²

Area of the path = 3846.5 m²- 3419.46  m²

=> 427.04 m²

Mark it as the brainliest!!

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Answer 2

Given:-

Width of the path = 4 m

Diameter of the flower bed = 66 m

To find:-

The area of the path.

Solution:-

Diameter of the flower bed is 66 m.

So, Radius of the flower bed =diameter/2

= (66/2)m

= 33m.

Now, Area of flower bed =  π r²

⟹ Area = 3.14 × (33)²

⟹Area = 3.14 × 1089.

⟹Area = 3419.49 m²

Now, Diameter of large circle

= Width of path + diameter of flower bed.

= ( 66 + 4)m

= 70m

So, Radius of large circle

= (diameter/ 2)

= (70/2)m

= 35 m.

Now, Area of large circle =  π r²

➟Area = 3.14 × (35)²

➟Area = 3.14 × 1225.

➟Area = 3846.5

So, now Area of path

= Area of large circle - Area of flower bed

= 3846.5 - 3419.49

= 427.01 m² (ans)

Therefore, the area of the path is 427.01 m².

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