A circular Flower bed is surrounded by a path 4m wide. The perimeter of the flower bed is 66m. What is the area of this path?
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hey here is ur answer......
Given that:-
Diameter of the flower bed(d) = 66 m
∴ Radius of the flower bed (r 1) = 33 m
So, the area of the flower bed (A1) = πr 1 2
= 3.14 x 33 x 33
= 3419.46 m2
Also the width of road is 4 m
∴ Radius of the flower bed with road (r 2) = (33 + 4) m
= 37 m
So the area of the flower bed with road (A2) = πr2 2
= 3.14 x 37 x 37
= 4298.66 m2
Hence the area of the road = (Area of the flower bed with road) – (Area of flower bed)
= A2 – A1
= 4298.66 - 3419.46 m2
= 879.20 m2
hope it helps u!!!
Given that:-
Diameter of the flower bed(d) = 66 m
∴ Radius of the flower bed (r 1) = 33 m
So, the area of the flower bed (A1) = πr 1 2
= 3.14 x 33 x 33
= 3419.46 m2
Also the width of road is 4 m
∴ Radius of the flower bed with road (r 2) = (33 + 4) m
= 37 m
So the area of the flower bed with road (A2) = πr2 2
= 3.14 x 37 x 37
= 4298.66 m2
Hence the area of the road = (Area of the flower bed with road) – (Area of flower bed)
= A2 – A1
= 4298.66 - 3419.46 m2
= 879.20 m2
hope it helps u!!!
797982p:
Tnx
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