A circular flower bed is surrounded by a path 4m wide. The diameter of the flower bed is 66m. ....what is area of this path (r=3.14
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Answered by
2
b=4m
d=66m
r=3.14
circumference=2^r
2×22/7×3.14
44×0.441
0.19404
=0.194
"
d=66m
r=3.14
circumference=2^r
2×22/7×3.14
44×0.441
0.19404
=0.194
"
Answered by
4
diameter of flower bed,d=66m
radius of flower bed or inner circle,r1=66/2=33m
radius of outer circle (which includes flower bed and circular path), r2=r1+width of path=33+4=37m
area of path= area of outer circle-area of flower bed =>Πr2^2 -Πr1^2
=>Π(r2^2-r1^2)
=>3.14(37^2-33^2)
= 879.2m^2
radius of flower bed or inner circle,r1=66/2=33m
radius of outer circle (which includes flower bed and circular path), r2=r1+width of path=33+4=37m
area of path= area of outer circle-area of flower bed =>Πr2^2 -Πr1^2
=>Π(r2^2-r1^2)
=>3.14(37^2-33^2)
= 879.2m^2
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