The car A of mass 1500kg travelling at 25m/s collides with another car B of mass 1000kg travelling at 15m/s in the same direction. After collision the velocity of car A is 26m/s then what is the velocity of car B after collision is
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According to the law of conservation of mass:
During collision, the total momentum before collision is equal to the total momentum after collision
The formula is:
m1u1 + m2u2 = m1v1 + m2v2
m1 = 1500 kg
m2 = 1000 kg
u1 = 25 m/s
u2 = 15 m/s
v1 = 26 m/s
So,
37500 + 15000 = 39000 + 1000v2
-> 52500 = 1000v2 + 39000
-> 1000v2 = 52500 - 39000
-> 1000v2 = 13500
-> v2 = 13500/1000
-> v2 = 13.5 m/s
Thus, the velocity of car B was 13.5 m/s after collision
During collision, the total momentum before collision is equal to the total momentum after collision
The formula is:
m1u1 + m2u2 = m1v1 + m2v2
m1 = 1500 kg
m2 = 1000 kg
u1 = 25 m/s
u2 = 15 m/s
v1 = 26 m/s
So,
37500 + 15000 = 39000 + 1000v2
-> 52500 = 1000v2 + 39000
-> 1000v2 = 52500 - 39000
-> 1000v2 = 13500
-> v2 = 13500/1000
-> v2 = 13.5 m/s
Thus, the velocity of car B was 13.5 m/s after collision
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