The difference between the two acute angle of a right angle triangle is 40 grade.Find the angles in degress
abhi178:
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we right angle traingle has one 90 degree
let three angle A , B and C
then A+B+C=180=> A+C=90
a/c difference between two acute angle is 40 grade =72 degree
so, we can write C-A=72(assuming here C> A)
now solve both equation
then C=81 and A=9
here we change grade to degree
g/100=d/180
d=180 (g/100)=180 (40/100)=72 degree
let three angle A , B and C
then A+B+C=180=> A+C=90
a/c difference between two acute angle is 40 grade =72 degree
so, we can write C-A=72(assuming here C> A)
now solve both equation
then C=81 and A=9
here we change grade to degree
g/100=d/180
d=180 (g/100)=180 (40/100)=72 degree
please take it brainlist
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