Question

A Circular flower bed is Surrounded by a path 4m Wide. The diameter of the flower bed is 66 m. What is the area of this path? (take π = 3.14).​

Answer 1

Step-by-step explanation:

A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. The area of this path is 879.20 m2.

Answer 2

$\huge \mathcal \colorbox{deeppink}{{ \color{pink} \huge {Given♡:-}}}$

• The width of path =4m
• The diameter of the flower bed = 66m

$\huge \mathcal \colorbox{darkgreen}{{ \color{white} \huge {Find♡:-}}}$

• Area of path

$\huge \mathcal \colorbox{darkblue}{{ \color{pink} \huge {Solution♡:-}}}$

• $Radius \: of \: flower \: bed \: = \frac{66}{2} = 33m.$
• Radius of flower bed & path together 66m

• 33m + 4m = 37m.

• Area of flower bed & path together=πr²

3.14 × (37 m)²

3.14 × 1369m²

=4, 298.66m²

• Area of flower bed = πr²

3.14x (33m)²

3.14x 1,089m²

= 3,419.46m².

• Area of path = Area of flower bed & path together - Area of flower bed.

4298.66 m² - 3 419.46m² = 879.20m².

Therefore, the area of this path is 879.20m²

____________________

$\begin{gathered}\begin{gathered}\dag\frak \red{Learn \: more \: about \: formulas \: of \: area\:and\:perimeter\:}\begin{cases}\sf{\;\;\; \red \divideontimes \: Perimeter \: of \: a \: square \: \bf{ = 4 × side}}\\\sf{\;\;\; \red\divideontimes Perimeter \: of \: a \: rectangle \: \bf{= 2 × (length + breadth) }}\\\sf{\;\;\;\red\divideontimes Area \: of \: a \: square \: \bf{= side × side \: or \: (Side)² }}\\\sf{\;\;\; \red\divideontimes Area \: of \: a \: rectangle \: \bf{= length × breadth}}\\\sf{\;\;\; \red\divideontimes \: Area \: of \: a \: parallelogram \bf{= base × height}}\\\sf{\;\;\; \red\divideontimes \: Area \: of \: a \: triangle \bf = \frac{1}{2} × (area \: of \: the \: parallelogram \: generated \: from \: it) \bf{= \frac{1}{2} \times base \times height }}\\\sf{\;\;\; \red\divideontimes Circumference \: of \: a \: circle \: \bf{= 2πr \: or \: πd }}\\\sf{\;\;\;\red\divideontimes Area \: of \: a \: circle \: \bf{= πr²}}\end{cases}\end{gathered} \end{gathered}$