Question

A circular garden has a circumference of 440m.there is a 7m wide path inside the garden along its boundary.what is the area of the path?

Answer 1

Answer:

The area of the path is  931.8 π  or 2925.85 m².

Step-by-step explanation:

If a circumference s 440 m:

2 r π = 440

r * 3.14 = 440 : 2

r  = 220 : 3.14 = 70.06 m

The inner radius : 70.06 - 7 = 63.06 m

The area of the path:

A = ( 70.3²  -  63.06² ) * π

A = 931.8 π = 2925.85 m²

Answer 2

Answer:

$2926 m^2$

Step-by-step explanation:

Circumference of circle = $2 \pi r$

A circular garden has a circumference of 440 m.

Sp. $440=2 \pi r$

$440=2 \times \frac{22}{7} \times r$

$\frac{440 \times 7}{2 \times 22}=r$

$70=r$

So, the radius of the circular garden(R) is 70 m

Now we are given that here is a 7m wide path inside the garden along its boundary

So, Inner radius (r) = 70 m - 7m = 63 m

Area of Path = Outer Area - Inner Area

                    = $\pi R^2 - \pi r^2$

                    = $\frac{22}{7}( 70^2 - 63^2)$

                    = $2926 m^2$

Hence the area of the path is  $2926 m^2$