A Circular garden has a radius
42m. A 7m wide road runs on
the outside around it. Find the
cost of constructing the road at
Rs. 15 per m².
Answers
Answer:
Outer radius with road is 42+7 = 49m
Area of this circle is pie r^2 = 3.14×49×49
= 7539.14m^2
Inner radius of cirle is 42m
Therefore its area is 3.14×42×42
= 5538.96m^2
Area of road = Outer circle - Inner circle
= 7539.14 - 5538.96
= 2000.18m^2
Therefore cost of constructing road
= 2000.18 × 15
= Rs 30,002.7
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Answer:
radius of inner circle :- 42m.
radius of outer circle :- 42 + 7 = 49 m.
area of circle = πr^2.
area of inner circle = 22/7 × 42 ×42.
= 22 × 6 × 42 = 132 × 42 = 5544cm^2
area of outer circle = 22/7 × 49 × 49
= 22 × 7 × 49
= 154 × 49
= 7546..
area of outer circle without inner circle =
= 7546 - 5544 = 2002m^2
cost of construction = 2002 × 15
= 30030 rupees......
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