A circular garden has a radius 42m. A 7m wide road runs on the outside around it. Find the cost of constructing the road at 15 rupees per m.sq.
Answers
Answer:
radius of the circular garden(r) = 42m
width of the road =7m
radius of the larger circle formed including the path =(42+7) = 49m (R)
volume of the road = volume of the larger circle - volume of the smaller circle
= πR^2 -πr^2
= π (R^2-r^2)
= π (R+r) (R-r)
= 22/7 × (49+42)×(49-42)
=22/7× 91 ×7
=22×91
= 2002m^2
cost of constructing per m =₹15
total cost = ₹(2002×15)
= ₹ 30030
Answer:
radius of the circular garden(r) = 42m
width of the road =7m
radius of the larger circle formed including the path =(42+7) = 49m (R)
volume of the road = volume of the larger circle - volume of the smaller circle
= πR^2 -πr^2
= π (R^2-r^2)
= π (R+r) (R-r)
= 22/7 × (49+42)×(49-42)
=22/7× 91 ×7
=22×91
= 2002m^2
cost of constructing per m =₹15
total cost = ₹(2002×15)
= ₹ 30030
Step-by-step explanation: