Question

A coolie lift a15 kg mass by 1.5 meter from the earth on his head. Find the work done by the coolie?

Answer 1

$\underline{ \mathfrak{\huge{\boxed{\fcolorbox{purple}{orange}{\purple{Answer\::-}}}}}} \\ \\ \huge{\star} \rm \: \underline{\boxed{ \huge \rm{\red{W} \blue{O} \green{R} \orange{K}}}} \\ \\ \leadsto \rm \: work \: done \: by \: force \: is \: given \: by \\ \\ \dagger \: \: \underline{ \boxed{ \rm{ \bold{ \pink{W = \vec{F} { \tiny{ \bullet}} \vec{d} = Fd \cos{ \theta}}}}}} \: \: \dagger \\ \\ \leadsto \rm \: where \: \theta = angle \: between \: force \\ \rm \: and \: displacement... \\ \\ \leadsto \rm \: here \: is \: only \: gravitational \: force \\ \rm \: acts \: in \: this \: condition \: and \: direction \\ \rm \: of \: force \: is \: downward \: whereas \\ \rm \: direction \: of \: displacement \: is \: eastward. \\ \\ \leadsto \rm \: hence \: angle \: between \: Force \: and \\ \rm \: displacement \: is \: 90 \degree \\ \\ \therefore \rm Work = Fd \cos90 \degree \\ \\ \therefore \: \underline{ \boxed{ \bold{ \purple{ \rm{W = 0 \: J}}}}} \: \: ( \because \rm \: cos90 \degree = 0)$