A circular grassy pot of land of diameter 42m has a path of wide 3.5 m running around it on the outside . find the cost of gravelling the path at rs4 per square metre
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Step-by-step explanation:
Answer:
Rs.2000.18
Step-by-step explanation:
Inner Diameter = 42 m
inner radius r = 42/2 = 21 m
Since we are given that A circular grassy plot of land has a path 3.5 m wide running around it outside.
So, outer radius R = inner radius +width = 21+3.5 = 24.5 m
Area of path outside = Outer Area - inner area
=\pi(R^2-r^2)π(R
2
−r
2
)
=3.14(24.5^2-21^2)3.14(24.5
2
−21
2
)
=500.045m^2500.045m
2
Cost of graveling of 1 square meter= rs 4
Cost of graveling of 500.045 square meter= 4*500.045= Rs.2000.18
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