A circular ground of radius 7m is surrounded by a path of width 3.5 m
Answers
Answered by
1
Answer:
Step-by-step explanation:
Radius of path + circular ground = 14m
(area of ground + path) - (area of ground)
(Pi * 14^2) - ( Pi * 7^2)
615.75 - 153.94
= 461.8 m^2 (the area of the path)
Hope this helps.
:-)
Answered by
2
Answer:
Step-by-step explanation:
Area of path=π(R^2-r^2)
R=10.5
r=7
A path=22/7×(10.5+7)(10.5-7)
A=22/7×(17.5)(3.5)
A=192.5
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