A circular cone has a base of radius 10 cm and height 25 cm. The area of the cross section of the cone by a plane parallel to its base is 154 cm square. Find the distance of the plane from the base of the cone
Answers
Given data:
The circular cone has a base of radius 10 cm and height 25 cm.
The area of the cross section of the cone by a plane parallel to its base is 150 cm square.
To find:
The distance of the plane from the base of the cone.
Solution:
We draw the attached figure. (Check the picture)
Let the radius of the cross section be r cm.
Then the area of the cross section is πr² cm square.
Given, πr² = 154
or, 22/7 × r² = 154
or, r² = 7/22 × 154
or, r² = 7 × 7
or, r² = 7²
or, r = 7
So, the radius of the cross section is 7 cm.
Let the distance of the plane from the base is x cm.
Then we can draw two triangles ADE and ABC, which are similar triangles.
From the property of similar triangles, we can write:
AD / AB = DE / BC
or, (25 - x) / 25 = 7 / 10
or, 10 (25 - x) = 175
or, 250 - 10x = 175
or, 10x = 75
or, x = 7.5
Answer:
Therefore the distance of the plane from the base of the cone is 7.5 cm.
Step-by-step explanation:
Given data:
The circular cone has a base of radius 10 cm and height 25 cm.
The area of the cross section of the cone by a plane parallel to its base is 150 cm square.
To find:
The distance of the plane from the base of the cone.
Solution:
We draw the attached figure. (Check the picture)
Let the radius of the cross section be r cm.
Then the area of the cross section is πr² cm square.
Given, πr² = 154
or, 22/7 × r² = 154
or, r² = 7/22 × 154
or, r² = 7 × 7
or, r² = 7²
or, r = 7
So, the radius of the cross section is 7 cm.
Let the distance of the plane from the base is x cm.
Then we can draw two triangles ADE and ABC, which are similar triangles.
From the property of similar triangles, we can write:
AD / AB = DE / BC
or, (25 - x) / 25 = 7 / 10
or, 10 (25 - x) = 175
or, 250 - 10x = 175
or, 10x = 75
or, x = 7.5
Answer:
Therefore the distance of the plane from the base of the cone is 7.5 cm.