Question

A circular loop has a resistance of 4002. Two points P and Q of the loop, which are one quarter of the circumference apart are connected to a 24 V battery, having an internal resistance of 0.52 What is the current flowing through the battery? (a) 0.5 A (b) IA (c) 2A (d) 3A

how the resistance find??​

Answer 1

Answer:

Anything that have mass and occupies space.

is called matter.

Answer 2

Explanation:

A circular loop has a resistance of 40Ω. 

Two points P and Q of the loop, which are one quarter of the circumference apart

Resistance of Each part = (1/4) 40 = 10Ω and (3/4) 40 = 30Ω

10Ω II 30Ω 

1/R = 1/10 + 1/30

1/R = (3 + 1)/30 

⇒R = 30/4

R = 7.5Ω. 

internal resistance of 0.5 Ω. 

Total Resistance = 7.5 + 0.5 = 8 Ω

Voltage applied = 24V 

Current = 24/8 = 3A 

3A current flowing through the battery.