Question

!) A circular loop of area 0.01 m2 and carrying a
current of 10amp is placed perpendicular to a
magnetic field of intensity of 0.1 tesla. The
torque ( in Nm) acting on the loop is
a)1.1
b) 0.8
c)0.001
d)0.01​

Answer 1

Answer:

option D is correct answer

Explanation:

A=0.01m

2

,I=10A,B=0.1T,θ=90

o

,sinθ=1

Now magnetic moment M =I×A

Torque, τ=

M

ˉ

×

B

ˉ

=MBsinθ

=IAB

=10×0.01×0.1=0.01Nm.