Physics, asked by PrakasahPrince284, 9 months ago

A circular loop of radius R carries a current I. Another circular loop of radius r(<

Answers

Answered by bhuvna789456
14

Explanation:

To find: The torque acting on the smaller loop.

Given data in the question  :

To the outer loop,

Current Magnitude = I

Loop Radius = R

The magnetic field at the center is thus supplied by the larger loop

B=\frac{\mu_{0} I}{2 R}

Let A be the smaller loop field, and let current pass through it.

Angle between the smaller loop area vector and the magnetic field due to the larger loop = 90°

The required torque is therefore given by the

\Gamma=i(\vec{A} \times \vec{B})

=\mathrm{i} \mathrm{AB} \sin 90^{\circ}

we know that |A|=\pi r^{2},|B|=\frac{\mu_{0} l}{2 R}

=i \pi r^{2} \frac{\mu_{0} I}{2 R}

==\frac{\mu_{0} I i \pi r^{2}}{2 R}

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