Physics, asked by carlwilkinson250, 10 months ago

A long, cylindrical tube of inner and outer radii a and b carries a current i distributed uniformly over its cross section. Find the magnitude of the magnitude filed at a point (a) just inside the tube (b) just outside the tube.

Answers

Answered by bhuvna789456
24

Explanation:

The magnitude of the magnetic field at a point (a) just inside the tube:

In any conducting tube, the magnetic field is always zero.

There is zero magnetic field inside the tube.

The magnitude of the magnetic field at a point (b) just outside the tube.

Let the point with distance b outside the tube be P.

Considering an American loop , as the figure shows.

loop Length, l=2 \pi \times b=2 \pi b

Enclosed current in the loop = I

If we apply the law of Ampere, we obtain

\int B \cdot d l=\mu_{0} i

B \times 2 \pi b=\mu_{0} i

B=\frac{\mu_{0} i}{2 \pi b}

Attachments:
Similar questions