A circular park has a path of uniform width around it. The difference
between outer and inner circumferences of the circular path is 132m. Find
the width of the path.
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Answer:
Let r
1
and C
1
be the radius and the circumference of the outer circle.
Let r
2
and C
2
be the radius and the circumference of the inner circle.
The width of the circular path is (r
1
−r
2
) m.
Given, C
1
−C
2
=132 m
⇒2πr
1
−2πr
2
=132
⇒2π(r
1
−r
2
)=132
⇒r
1
−r
2
=
7
22
66
⇒r
1
−r
2
=21
Thus, width of the circular path is 21 m.
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