A circular park has a path of uniform width around it. The difference between the outer and inner areas of the circular park is 132 m² and its width is 3.5 m, then the radius of inner circular park is
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Given,
2πr2−2πr1
= 132
⇒r2−r1 = 132/2π
= 132×7/44m
=21m
i.e., width of the path =21m
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