Question

a circular park of a diameter 28m has a circular path of width 3.5m along the boundary of the park.find the area of the path?​

Answer 1

Answer:

This is simple maths.......

Step-by-step explanation:

If d= 28 m then r= 14 m

Area of circular park = πr^2=3.14×14^2 = 615.44 m2

Park Area without path = π(r-3.5)^2 = 346.185 m2

thus path area = 615.44-346.185= 269.255 m2

Answer 2

The area of path is 346.5 sq.m.

Step-by-step explanation:

Diameter of circular garden = 28 m

Radius of circular garden r=$\frac{28}{2}=14 m$

A circular park of a diameter 28m has a circular path of width 3.5m along the boundary of the park.

Outer radius = 14+3.5=17.5 m

Area of path = Outer area - Inner area

Area of path =$\pi R^2-\pi r^2$

Area of path = $\frac{22}{7}(17.5^2-14^2)=346.5 m^2$

Hence The area of path is 346.5 sq.m.

#learn more:

A circular Park of radius 110 metre has a circular path of width 8m running along the boundary inside the park. find the area of the path. ​

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