A circular park of radius 21 m has a road 7 m wide on its outside all around. Find the area of the road
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Answered by
71
Area of the park = 22/7*21*21 = 1386 sq.m
Radius of park including road = 21+7 = 28 m
Area of the park including = 22/7*28*28 = 2464 sq.m
So,
Area of the road = Area of the park including road - Area of the park excluding road
= 2464sq.m - 1386sq.m = 1078 sq.m Ans
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Radius of park including road = 21+7 = 28 m
Area of the park including = 22/7*28*28 = 2464 sq.m
So,
Area of the road = Area of the park including road - Area of the park excluding road
= 2464sq.m - 1386sq.m = 1078 sq.m Ans
<Hope it helps>
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priyanshu7903590883:
Its correct
Answered by
29
Radius of circle= 21 m(r)
Width of road =7m
Total radius of cirlce along with road =28m(R)
area of the Road= (area of circle along with road)-(area of circle)
=(πR^2)-(πr^2)
=(22/7×28×28)-(22/7×21×21)
=2464-1386
=1078sq m
Width of road =7m
Total radius of cirlce along with road =28m(R)
area of the Road= (area of circle along with road)-(area of circle)
=(πR^2)-(πr^2)
=(22/7×28×28)-(22/7×21×21)
=2464-1386
=1078sq m
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