A circular path runs around a circular flower bed if the circumference of the flower bed and path are 88 m and 132 m respectively, find the width of the path also find the area of path
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Circumference of the flower bed (inner circumference)= 88 cm
Circumference of the path (outer circumference)= 132
Let the outer and inner radii be R & r
Circumference of the circle= 2π r
Outer Circumference of a circle= 2πR
132 = 2× (22/7)×R
R= 132×( 7/22)(1/2)= (66×7)/22= 3×7= 21cm
Inner circumference of a circle= 2πr
88 = 2× (22/7)×r
r= 88×(7/22)×(1/2)= (4×7)/2= 2×7= 14cm
Width of a track =( R-r)= 21-14= 7 cm
Area of a circle= πr²
Area of outer circle= πR²= 22/7×(21)²
=( 22/7)× 21×21
= 22×3×21
=66×21
=1386 cm²
Area of outer circle= 1386 cm²
Area of inner circle= πr²
=( 22/7)× 14²
=( 22/7)×14×14
= 22×2× 14
=44×14= 616cm²
Area of inner circle= 616 cm²
Area of path= area of outer circle - area of inner circle
Area of path= 1386 - 616 = 770 cm²
Hence the width of a path is 7 cm an area of path is 770 cm²
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Hope this will help you...
Circumference of the flower bed (inner circumference)= 88 cm
Circumference of the path (outer circumference)= 132
Let the outer and inner radii be R & r
Circumference of the circle= 2π r
Outer Circumference of a circle= 2πR
132 = 2× (22/7)×R
R= 132×( 7/22)(1/2)= (66×7)/22= 3×7= 21cm
Inner circumference of a circle= 2πr
88 = 2× (22/7)×r
r= 88×(7/22)×(1/2)= (4×7)/2= 2×7= 14cm
Width of a track =( R-r)= 21-14= 7 cm
Area of a circle= πr²
Area of outer circle= πR²= 22/7×(21)²
=( 22/7)× 21×21
= 22×3×21
=66×21
=1386 cm²
Area of outer circle= 1386 cm²
Area of inner circle= πr²
=( 22/7)× 14²
=( 22/7)×14×14
= 22×2× 14
=44×14= 616cm²
Area of inner circle= 616 cm²
Area of path= area of outer circle - area of inner circle
Area of path= 1386 - 616 = 770 cm²
Hence the width of a path is 7 cm an area of path is 770 cm²
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Hope this will help you...
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