Question

A circular piece of thin wire is converted into a rhombus of side 11 cm . find the diameter of the circular piece

Answer 1

perimeter of rhombus= perimeter of circle
             4s                  = 2πr
               2r=4s/π
                   =4*11/(22/7)
                   =4*11*7/22
                   =14 cm.
2r = diameter so diameter = 14 cm.


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Answer 2

Perimeter of rhombus =$4s$
                                     4×11= 44 cm
⇒ Perimeter of circle is also 44cm ( as perimeter of rhombus = perimeter of circle)

 Perimeter of circle = $2 \pi r$ or $\pi d$
                 
  ⇒44cm=3.14×d
                   
 ∴d= $\frac{44}{3.14}$
         
   diameter = 14.02 cm