Question

A circular pond is of diameter 17.5m. It is surrounded by a 2m wide path. Find the cost of constructing the path at the rate of Rs. 25 per square meter(Use π=3.14)

Answer 1

Answer:

Given,

Diameter = 17.5

Radius = 8.75

Area of pond = 22/7 × 8.75 × 8.75

= 240.625

Again it is surrounded by 2m wide path

Therefore diameter = 17.5+2+2 = 21.5

Radius = 10.75

Area of pond along with path

= 22/7×10.75×10.75

= 363.196

Area of path = 363.196 - 240.625

= 122.571

Cost of constructing the path

= 122.571×25

= Rs 3061.50

Step-by-step explanation:

please Mark as brainlist

Answer 2

Radius of the circular pond, r1 = $\sf{\frac{17.5}{2}m=8.75m}$

Radius of the outer circle, r2 = $\sf{8.75m+2m=10.75m}$

Area of the path °

$\longrightarrow$$\sf\red{\pi( {r2}^{2} - {r1}^{2} )}$

$\longrightarrow$$\sf\red{3.14 = ( {(10.75)}^{2} - {(8.75)}^{2} {m}^{2} }$

$\longrightarrow$$\sf\red{3.14(10.75 + 8.75)(10.75 - 8.75) {m}^{2}}$

$\longrightarrow$$\sf\red{3.14 \times 19.5 \times 2 {m}^{2}}$

$\longrightarrow$${\boxed{\sf{\red{122.46m}^{2}}}}$

Hence, the cost of constructing the path at the rate of $\sf{Rs.25/{m}^{2}}$

= $\sf\purple{122.46 \times 25}$

= ${\boxed{\sf{\purple{3061.50}}}}$