Question

a circular pond is of diameter 17.5m . It is surrounded by a 2m wide path . Find the cost of constructing a road in this path at rate of 25 per square metre.​

Answer 1

Cost of construction is Rs. 3061.25

Step-by-step explanation:

Given :

Diameter = 17.5 m and width of the path(w) = 2 m

Radius of the circular pond (r) = $\frac{17.5}{2} = 8.75 \text{m}$

Radius of the circular pond and path (R) = r + w = 8.75 + 2 = 10.75 m

Area of the path = Area of circular pond along with path - Area of the circular pond

                         = $\pi \text{R}^{2} - \pi \text{r}^{2}$

                         = $\pi (\text{R}^{2} - \text{r}^{2} )$

                          = $3.14 \text{x} ( 10.75^{2} - 8.75^{2} )$

                          $= 3.14 \text{x} (115.56 - 76.56)\\= 3.14 \text{x} 38.99\\= 122.45 \text{m}^{2}$

Cost of construction = 25 x 122.45 = Rs.3061.25

To Learn More....

1. A circular pond of of 21m in diameter. it is surrounded by 3.5m wide path. find the surface area of constructing the path at the rate of Rs.25 per metre.

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