Question

A circular pond is surrounded by a 2 m wide circular path. If the outer circimference of the circular path is 44 m find the inner circumference of of the circular path. Also find the area of the path

Answer 1

Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️⬇️

Let R be the radius of the Outer circular path ..

and the Circumference of outer circular path is given 44m ..

So ,

2∏R = 44

∏R = 22

R = 7 m ..

Now width = 2m .

Inner radius (r) = 7 - 2

r = 5 m ..

Inner circumference

2πr

2 × 22/7 × 5

220/7

31.42 m

Area of path ..

Outer area of circular path - inner Area ..

∏R² - ∏r²

∏(7)² - ∏(5)²

$\frac{22}{7} \times 49 - \frac{22}{7} \times 25 \\ \\ 154 - 78.57 \\ \\ 75.43 {m}^{2}$

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I HOPE IT WILL HELP YOU

Thank you

☺️

Answer 2

$dear friend$
here is your solution ☺☺☺

☺☺☺☺Suppose R be the outer circumference of circular path.
Outer circumference of circular path = 2πR = 44 m
⇒2×227×R = 44⇒R = 44×72×22 = 7
So, radius of inner circular path = radius of outer circular path - width of the path = 7 - 2 = 5 m
So, inner circumference of circular path = 2πR = 2×227×5 = 31.42 m
Area of the path = area of the outer circular path - area of inner circular path
= π72-π52= 227×49-227×25= 154-78.57= 75.43 m2

$thanks$