Question

A circular pond is surrounded by a 2 m wide circular path. If outer circumference of circular path is 44 m, find the inner circumference of the circular path. Also find area of the path

Answer 1

Answer :

Let, the radius of the outer circle be R m

Then, its circumference = 2πR m

    ⇒ 2πR = 44

    ⇒ R = 44/(2π)

    ⇒ R = 7, since π = 22/7

So, the radius of the outer circle is 7 m

If r m be the radius of the inner circle, then

    r = 7 - 2 m = 5 m

Thus, the inner circumference of the circular path be

    = 2πr m

    = 2π * 5 m

    = 10π m

    = 31.4 m, where π = 3.14

The area of the inner circle

    A1 = πr² m²

    = π * 5² m²

    = 25π m²

and the area of the outer circle

    A2 = πR² m²

    = π * 7² m²

    = 49π m²

∴ the area of the circular path

    = A2 - A1

    = (49π - 25π) m²

    = 24π m²

    = 24 * 3.14 m²

    = 75.36 m²

#MarkAsBrainliest

Answer 2

Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️⬇️


Let R be the radius of the Outer Circumference ..
And the Circumference of the Outer circular path is 44 ..

So ,

2∏R = 44

∏R = 22

R = 7 m ..

Radius of inner part (r) = Radius of outer Circumference - width of path .

r = 7 - 2

r = 5m .


Inner Circumference of the Circle .

2 × 22/7 × 5

31.42 m ..


Area of path ..


Area of outer circular path - area of inner circular path ..

∏(7)² - ∏(5)²

$. \frac{22}{7} \times 49 - \frac{22}{7} \times 25 \\ \\ 154 - 78.57 \\ \\ 75.43 {m}^{2}$


===========================


I HOPE IT WILL HELP YOU

Thank you

☺️