Math, asked by parRagattu, 1 year ago

a circular pond of of 21m in diameter. it is surrounded by 3.5m wide path. find the surface area of constructing the path at the rate of Rs.25 per metre.

Answers

Answered by Sreesha
4
d= 21m
so r of pond = 21/2m = 10.5m
    R of pond including path = 10.5 + 3.5
                                          = 14m

  A of pond                        = pie R^2 - pie r^2
                                         = 14^2 - 10.5^2
                                          = 196 - 110.25
                                         = 85.75 m^2

A of path                          = 22/7 * 85.75
                                        = 269.5 m^2

Cost of constructing path = rs 25/m^2
                                         = rs 25 * 269.5 m^2
                                         = Rs. 6737.5 
                                         = Rs. 6738 (appx.)
Similar questions