a circular pond of of 21m in diameter. it is surrounded by 3.5m wide path. find the surface area of constructing the path at the rate of Rs.25 per metre.
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d= 21m
so r of pond = 21/2m = 10.5m
R of pond including path = 10.5 + 3.5
= 14m
A of pond = pie R^2 - pie r^2
= 14^2 - 10.5^2
= 196 - 110.25
= 85.75 m^2
A of path = 22/7 * 85.75
= 269.5 m^2
Cost of constructing path = rs 25/m^2
= rs 25 * 269.5 m^2
= Rs. 6737.5
= Rs. 6738 (appx.)
so r of pond = 21/2m = 10.5m
R of pond including path = 10.5 + 3.5
= 14m
A of pond = pie R^2 - pie r^2
= 14^2 - 10.5^2
= 196 - 110.25
= 85.75 m^2
A of path = 22/7 * 85.75
= 269.5 m^2
Cost of constructing path = rs 25/m^2
= rs 25 * 269.5 m^2
= Rs. 6737.5
= Rs. 6738 (appx.)
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