Question

a circular pond of of 21m in diameter. it is surrounded by 3.5m wide path. find the surface area of constructing the path at the rate of Rs.25 per metre.​

Answer 1

Step-by-step explanation:

The area of the circular pond is 22/7*(21/2)power2

=693/2=346.5 m2

The total diameter of the pond with the wide path is

22/7*28/2*28/2

=616 m2

Then area of the path is

=616-346.5

269.5 m2

The rate is 269.5*25=6737.5 rupees

Answer 2

Answer:

Step-by-step explanation:

Area of circular pond is pi * (d/2)^2 = pi *  10.5^2 = 110.25pi

now when the wide path is there then diameter = 21+3.5+3.5=28

now new Area = pi * (d/2)^2 = pi * 14^2 = 196pi

total area of wide path = new Area - Original Area = (196pi-110.25pi)

cost of 1 m^2 = Rs 25

therefore cost of (196pi-110.25pi)m^2 = 25* (196pi-110.25pi) = Rs6734.79