Question

a circular racing track has inner circumference 528 M and Outer circumference 616 cm find the width of the track

Answer 1

2π ( R-r) = 616-528 = 88 m
(R-r) = 88/2π = 88*7/2*22 = 14 m
so width of track = 14 m

Answer 2

first whole circumference=2pir
outer circle=616
616 =2×22/7×r
616×7/2×22=r
616/22=28 ,28/2=14 14×7=98
so whole radius=98
inner circumference=528
528=2×22/7×r
528×7/2×22=r
528/22=24; 24/2=12,12×7=84
now outer circumference rafius - inner circumference radius=98-84=14
track width is 14 m