a circular racing track has inner circumference 528 meteŕ and Outer circle forest 616 m find the width of the track
Answers
Answered by
2
Inner circumference = 528 m.
2 π r = 528 m.
2×22/7× r = 528
r = 84 m.
Outer circumference = 616 m.
2 π r = 616 m.
2 ×22/7× r = 616
r = 98 m.
Width of the track = 98-84
= 14 m.
2 π r = 528 m.
2×22/7× r = 528
r = 84 m.
Outer circumference = 616 m.
2 π r = 616 m.
2 ×22/7× r = 616
r = 98 m.
Width of the track = 98-84
= 14 m.
hugekkk:
bhumika can u inbox me
Similar questions