a circular ring if 6 kg and radius a is placed such that its centre lies at the orgin. two particles of masses 2 kg each are placed at the intersecting
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Answer:
Hi friend
Hope this answer helps
Explanation:
Ring has center of mass at (0,0)
the particle on +x axis will be at (a,0)
the particle on +y axis will be at (0,a)
so the center of mass will be at x=
6kg+2kg+2kg
6×0+2×a+2×0
= 5a
and y=
6kg+2kg+2kg
6×0+2×0+2×a
= 5a
the angle with x axis will be tan −1
xy =45
0
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