Question

A circular ring with a force M and a radius R, passes through its center and its plane corresponds to the perpendicular axis. Now two objects with equal force M are placed at its point of intersection, now the angular velocity of the ring is w'=? ​

Answer 1

Answer:

Moments of inertia (MOI) of the ring before attaching the masses I= MR

2

,

MOI of the ring after attaching the masses I

′

=(M+2m)R ^2

Let angular momentum after the attaching the masses w

Since there is no external torque, so we use conservation of angular momentum.

I×w=I '×w

′

⇒MR ^2×w= MR^2 × w'/M +2m

⇒w' = wM/ M + 2m

Explanation:

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