A circular road of radius 50 m has the angle of banking equal to 30°. At what speed should a vehicle go on this road so that the friction is not used?
Answers
Angle of Banking (θ) = 30°
Radius of the Path or Radius of the Curvature = 50 m.
We know that in case a road is banked and no Friction is used, then,
N Cos θ = mg ------eq(i)
and N Sin θ = mv²/r ------eq(ii)
Dividing (ii) from (i) equation,
tan θ = v²/rg
Now,
tan 30° = v²/50 × 10
⇒ v² = 500/√3
⇒ v² = 288.67
∴ v = 16.9 m/s.
Hence, the speed of the vehicle is 16.9 m/s.
Hope it helps.
Answer:
Angle of Banking (θ) = 30°
Radius of the Path or Radius of the Curvature = 50 m.
We know that in case a road is banked and no Friction is used, then,
N Cos θ = mg ------eq(i)
and N Sin θ = mv²/r ------eq(ii)
Dividing (ii) from (i) equation,
tan θ = v²/rg
Now,
tan 30° = v²/50 × 10
⇒ v² = 500/√3
⇒ v² = 288.67
∴ v = 16.9 m/s.
Hence, the speed of the vehicle is 16.9 m/s.
Explanation: