Question

a circular road runs around a circular Garden if the circumference of the outer circle and the inner circle are 110 M and 88 M find the width of the road

Answer 1

hope it helps and sorry for to be late

Answer 2

Answer:

3.5 m

Step-by-step explanation:

Circumference = $2\pi r$

Since we are given that  the circumference of the outer circle is 110 m

So,  $110 = 2\pi r$

Where r is the radius of outer circle .

$55 = \frac{22}{7} r$

$55 \times \frac{7}{22}= r$

$5 \times \frac{7}{2}= r$

$\frac{35}{2}= r$

$17.5= r$

Thus the outer radius is 17.5 m

Now we are also given that circumference of the the inner circle is 88 m .

So,  $88 = 2\pi r$

$44 = \frac{22}{7} r$

$44 \times \frac{7}{22}= r$

$4 \times \frac{7}{2}= r$

$14= r$

Thus the inner radius is 14 m.

Width of road = Outer radius - inner radius

                       = 17.5 - 14

                       = 3.5 m

Thus the width of the road is 3.5 m