A circular road runs around a circular ground. If the difference between the circumference of inner and outer circle is 66 cm . Find the width of the road .
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Answer:
10.5 m
Step-by-step explanation:
Let radius of outer circle = R
and radius of inner circle = r
ATQ,
2π−2πr=66
2π(R−r)=66
R−r=66/2π = 66×7 / 2×22 = 21/2
width=10.5m
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