Question

A circular road runs around a circular ground. If the difference between the circumference of inner and outer circle is 66 cm . Find the width of the road .
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Answer 1

Answer:

10.5 m

Step-by-step explanation:

Let radius of outer circle = R

and radius of inner circle = r

ATQ,

 2π−2πr=66

2π(R−r)=66

R−r=66/2π = 66×7 / 2×22 = 21/2

width=10.5m