a circular road runs around a circular ground .If the differences between the circumference of the outer circle and the inner circle is 66 M, find the width of the road
pramodjani5:
ans 21/2
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Difference of circumference=66m
2pi(R-r) =66m
(R-r)=66/2pi
=66/(2 x 22/7)=21/2m
here (R-r) is width of road=10.5m
2pi(R-r) =66m
(R-r)=66/2pi
=66/(2 x 22/7)=21/2m
here (R-r) is width of road=10.5m
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