in a triangle the measure of the second angle is 20 more than twice the first and the measure of the third is 55 more than one-third of the first. find the measure of the angles of the triangle
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let the first angle be x
then 2nd angle= x+20
3rd angle=x+55
their sum is 180
x+x+20+x+55=180
3x+75=180
3x=180-75=105.
x=105/3=35
first angle=x=35
2nd angle=x+20=35+20=55
3rd angle=x+55=35+55=90
then 2nd angle= x+20
3rd angle=x+55
their sum is 180
x+x+20+x+55=180
3x+75=180
3x=180-75=105.
x=105/3=35
first angle=x=35
2nd angle=x+20=35+20=55
3rd angle=x+55=35+55=90
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