Question

A circular road runs around a circular
ground. If the radius of the ground is 7 m and
the difference between the circumferences of
the outer circle and the inner circle is 44 m
then the area of the road is:​

Answer 1

Answer:

Let radius of outer circle = R

and radius of inner circle = r

ATQ 2π−2πr=66

2π(R−r)=66

R−r=662π=66×72×22=212

width=10.5m

Explanation:

A circular road runs around a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is : (Takeπ=227)