Question

A circular road runs around the circular ground if the difference between the cicumferences of the outer circle and inner circle is 66 meters find the width of the road

Answer 1

difference of circumference=66m
2pi(R-r) =66m
(R-r)=66/2pi
=66/(2 x 22/7)=21/2m
here (R-r) is width of road=10.5m

Answer 2

Let the Radius of outer circle be R
and Radius of inner circle be R

2πR-2πr = 66
π(R-r) = 33
22/7 (R-r) =33
R-r = 10.5


Hence the width of the road
= Difference between radii of the circles
= R-r
= 10.5 m