Question

A circular road runs round a circular ground if the difference between the circumferences of the outer circle and the inner circle is 66 metres find the width of the road.

Answer 1

Hey user !!

Here's the answer you are looking for

Let the radius of outer circle be R meters and the radius of smaller circle be r meters.

The formula for circumference is 2πr where r is the radius.

According to the question,

Circumference of outer circle - circumference of inner circle = 66m

And the width of the road is (R - r)m

So, 2πR - 2πr = 66

2π(R - r) = 66

$(R - r) = \frac{66}{2\pi} \\ \\ (R - r) = \frac{66 \times 7}{2 \times 22} \\ \\ (R - r) = \frac{21}{2} = 10.5m$

Therefore, the width of the road is 10.5m

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