Question

A circular tent is cylindrical to a height of 3 meters and conical above it. If its diameter is 105 m and the slant height of the conical portion is 53 m, calculate the length of the canvas 5 m wide to make the required tent.

Answer 1

Surface area of Tent= surface area of the cylinder + surface area of the cone
=(2*pi*r*h)+ (pi*r*l)
=2*(22/7)*(105/2)*3+(22/7)*(105/2)*53
=9735 sq.m
l*b=9735
b=5m,
l=9735/5 => l=1947m

Answer 2

The length of the canvas is $1947m$

Step-by-step explanation:

Given,

Height of cylindrical tent is $h=3m$

Diameter of base is $d=105m$

Radius of base is $r=\frac{105}{2}=52.5m$

Slant height of the conical portion is $l=53m$

Wide of the canvas is $b=5m$

∴ Surface area of Tent=Surface area of the cylinder+Surface area of the cone

⇒Surface area of Tent$=2\pi r h+\pi r l$

⇒Surface area of Tent$=(2\pi \times52.5 \times 3)+(\pi \times52.5 \times 53)$

⇒Surface area of Tent$=9735m^{2}$

Area of the canvas is$=l\times b$

∴ $(l\times b)=9735$

⇒$l=\frac{9735}{5}=1947m$

So, The length of the canvas is $1947m$