A circular track of radius 400m is kept with outer side of track raised to make 5 degree with the horizontal. What is the process called and why is it done?
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9
Answer:
Vm=34.21m/s
Hope it helps you.
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Answered by
10
Explanation:
This process is called Banking of Road and it is done to avoid the risk of skidding and wear & tear of tyres.
There is question which is not mentioned in the yours. We need to find the maximum velocity that a body can move along that curve.
The sub question gives the coefficient of frictional force μ = 0.2
We know that:-
√rg(μ + tanθ)
Vₘₐₓ = --------------------
√(1-μtanθ)
Substituting the values as:
r = 400m,
θ = 5°,
μ = 0.2,
g = 9.8 m/s²
Vₘₐₓ ≃ 34m/s
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