Physics, asked by Azrmehmood38991, 9 months ago

A circular track of radius 400m is kept with outer side of track raised to make 5 degree with the horizontal. What is the process called and why is it done?

Answers

Answered by HasiniGogineni
9

Answer:

Vm=34.21m/s

Hope it helps you.

Attachments:
Answered by shuaibhamzap
10

Explanation:

This process is called Banking of Road and it is done to avoid the risk of skidding and wear & tear of tyres.

There is question which is not mentioned in the yours. We need to find the maximum velocity that a body can move along that curve.

The sub question gives the coefficient of frictional force μ = 0.2

We know that:-

√rg(μ + tanθ)

Vₘₐₓ = --------------------

√(1-μtanθ)

Substituting the values as:

r = 400m,

θ = 5°,

μ = 0.2,

g = 9.8 m/s²

Vₘₐₓ ≃ 34m/s

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